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A tank with an isosceles-triangular cross section with sides 4,4,and 6 meters, has a length of 10 meters, and is currently resting on the 6 meter by 10 meter face. The tank is filled with water to the depth of 1 meter. If the tank is placed on a triangular face, what would be the depth of the water in the tank?
  • A$$\frac{5}{7}(\sqrt{7}-{1})$$
  • B$$\frac{10}{7}(\sqrt{7}-{1})$$
  • C$$(\frac{10}{7})(\sqrt{7})$$
  • D$$\frac{10}{7}({2}\sqrt{7}-{1})$$
  • E$$\frac{20}{7}({2}\sqrt{7}-{1})$$
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正确答案: C

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